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  • X and R channels

    I'm trying to get my head round the X & R channels theory. In ITMD2 p.70 in the section headed "Phase Demodulation" there are some equations:

    X = Acosθ (eq. 7-1)
    R = Asinθ (eq. 7-2)

    Could someone define what "A" and "θ" are in this context? They aren't defined in the text and so I've been trying to reverse-engineer to deduce what they are but as I'm trying to learn this stuff reverse-engineering it is ambiguous. "θ" is fairly ubiquitous in meaning an angle, but which one? "A" could mean another angle, or something else - amplitude?

    Anyway if someone could put me out of my misery I'd be grateful.

    paul

  • #2
    Google Inverse Trigonometry. A= ARC

    Comment


    • #3
      Target receive signals have some amplitude (A) and some phase (θ) relative to the transmit signal. To extract these we use quadrature demodulation to get an X and R voltage value and then compute A = sqrt(X2+R2) and θ = arctan(R/X).

      Here are 5 targets that all show the same amplitude (A) but different phases. Phases are backwards from normal trig; ferrite is 0°, foil is 95°, and the silver quarter is 155°.

      Click image for larger version

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ID:	430718

      Comment


      • #4
        Originally posted by Altra View Post
        Google Inverse Trigonometry. A= ARC
        OK - I'm not convinced by that.

        1. A few equations further down (7-5), arctan is spelled out fully (ie "arctan" not "Atan"). Why would the style change from one equation to the next?
        2. In equation 7-4, the A term is eliminated when R is divided by X, (R/X = Asinθ/Acosθ = sinθ/cosθ).

        I suppose that since A is eliminated in a subsequent step then its meaning is academic. I'd still like to know what it is, however.

        Comment


        • #5
          Originally posted by Carl-NC View Post
          Target receive signals have some amplitude (A) and some phase (θ) relative to the transmit signal. To extract these we use quadrature demodulation to get an X and R voltage value and then compute A = sqrt(X2+R2) and θ = arctan(R/X).

          Here are 5 targets that all show the same amplitude (A) but different phases. Phases are backwards from normal trig; ferrite is 0°, foil is 95°, and the silver quarter is 155°.

          Click image for larger version

Name:	image.png
Views:	154
Size:	53.9 KB
ID:	430718
          Thanks! I guess that image is from your new book?

          Just going to read up on quadrature demodulation now. :-)

          Comment


          • #6
            Originally posted by Repwoc View Post
            Thanks! I guess that image is from your new book?
            Yes, and quadrature demodulation is covered extensively.

            Comment


            • #7
              Originally posted by Repwoc View Post

              OK - I'm not convinced by that.

              1. A few equations further down (7-5), arctan is spelled out fully (ie "arctan" not "Atan"). Why would the style change from one equation to the next?
              2. In equation 7-4, the A term is eliminated when R is divided by X, (R/X = Asinθ/Acosθ = sinθ/cosθ).

              I suppose that since A is eliminated in a subsequent step then its meaning is academic. I'd still like to know what it is, however.
              I stand corrected, some programming languages use atan, asin and acos for inverse functions. That's my reference for being wrong.

              Comment


              • #8
                Originally posted by Altra View Post

                I stand corrected, some programming languages use atan, asin and acos for inverse functions. That's my reference for being wrong.
                Actually when I read your post I thought "jeez why didn't I think of that?" but then it didn't fit with the following text.​

                Comment


                • #9
                  I didn't have any context and made a sloppy post. Carl wrote the book, A is for voltage amplitude, post #3

                  Comment


                  • #10
                    It is confusing, and it's my fault. I should have used A·cos(θ) instead of Acos(θ).

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