Announcement

Collapse
No announcement yet.

field test unit no 001 "model T"

Collapse
This topic is closed.
X
X
 
  • Filter
  • Time
  • Show
Clear All
new posts

  • Originally posted by Kev View Post
    This may have been the case with early GPs and the 5k but it is not necessarily so with the 3k5, 4k and 4k5. Some Q's for you Minelab stock DD TX-Q= 5.29, RX-Q= 0.152 Coiltek 14x9 Goldstalker Mono Q= 4 Coiltek 18x12 Goldstalker Mono Q= 3.78 Nugget Finder 14x9 Mono Q= 5.5 (yes that's right 5.5 and its a fantastic coil!) That 14x9 Nugget Finder is the most sensitive coil I've ever owned, it will get gram+ bits deeper than the 18x12 Coiltek and smaller sub gram bits deeper than the Coiltek 14x9. Often 0.05g bits up to an inch in caliche. I have built coils up to a Q of 5 and they have worked very well, not as good as the NF though. I aim for a Q of 4.5 to 4.8 Because Moodzs detector is not a Minelab he can engineer whatever coil parameters he so desires Kev.
    Kev the coil I tested worked fine on a 3000,3500 and some SD's and another person ran it OK on his 4500.

    Comment


    • Originally posted by robby_h View Post
      I quoted you Kev because I know the 3.9 figure doesn't universally apply, but Doug obviously doesn't now this.
      You would not have known this if Kev had not told you!!!! LOL!

      Comment


      • Originally posted by Doug2 View Post
        You would not have known this if Kev had not told you!!!! LOL!
        Doug,
        Does Q as measured with an RF Q meter indicate if a damped PI coil will work and does this figure truly represent Q for a damped PI coil? Do you know how JS measured Q?

        And Doug, look at Kev's figures for the Minelab stock DD.

        TX-Q= 5.29, RX-Q= 0.152

        Note the very low Q for the higher resistance RX coil?? Where does this leave your argument regarding high Q basket weave being a better RX antenna for PI?

        Comment


        • Originally posted by robby_h View Post
          Doug, Does Q as measured with an RF Q meter indicate if a damped PI coil will work and does this figure truly represent Q for a damped PI coil? Do you know how JS measured Q? And Doug, look at Kev's figures for the Minelab stock DD. TX-Q= 5.29, RX-Q= 0.152 Note the very low Q for the higher resistance RX coil?? Where does this leave your argument regarding high Q basket weave being a better RX antenna for PI?
          Can you list the commercial coils have you measured the Q of and what the Q value was? Can you then tell us which of these coils will or won't run on the various ML models? Basket or spider wound coils are more efficient rx antenna;s than an equivalent sized bundle wound! The reasons should be obvious to you!!!!!

          Comment


          • Originally posted by Doug2 View Post
            Can you list the commercial coils have you measured the Q of and what the Q value was? Can you then tell us which of these coils will or won't run on the various ML models? Basket or spider wound coils are more efficient rx antenna;s than an equivalent sized bundle wound! The reasons should be obvious to you!!!!!
            I see you are doing your usual and never answering any questions put to you Doug, and as usual your reply is a question.

            Comment


            • Is that the Q-factor of the coil you are talking about the following relationship?
              Q = XL/R = w*L/R = 2*pi*f*L/R, where
              f = 1 kHz (measurement frequency),
              L = coils inductance
              R = coils resistance

              Q = 2*pi*1000 * 300 µH/0.4 Ohm = 4.7
              (Yep, it must be.)
              ^sif

              Comment


              • Originally posted by robby_h View Post
                ... but he was talking about making ~40 per day and selling the things for 100 bucks each on Doug's forum.
                40/day * 100 bucks = 4000 donald ducks/day (stress, stress, stress -> making expensive)
                8/day * 500 bucks = 4000 donald ducks/day (you have less stress)

                You fire yourself and hire 5 ducks ->
                8/day * 5 ducks * 500 bucks = 20,000 donald ducks/day (you are going to make the donald duck dynasty)
                Not bad... I should go this way rich *LOL*

                ^sif

                Comment


                • Originally posted by Paul99 View Post
                  I see you are doing your usual and never answering any questions put to you Doug, and as usual your reply is a question.
                  What happened to your parrot cartoon here?

                  Comment


                  • Originally posted by Aziz View Post
                    Is that the Q-factor of the coil you are talking about the following relationship? Q = XL/R = w*L/R = 2*pi*f*L/R, where f = 1 kHz (measurement frequency), L = coils inductance R = coils resistance Q = 2*pi*1000 * 300 µH/0.4 Ohm = 4.7 (Yep, it must be.) ^sif
                    The mathematical definition of Q of a circuit is 2pi times the ratio of the maximum instantaneous energy to the energy dissipated over unit of time corresponding to one cycle. ie Q=2pi X energy stored/energy dissipated per cycle. At the instant the max energy stored in the inductance of a resonant circuit the amount of energy stored can be expressed as1/2L(Imax)^2 where I= current and L= inductance . The amount of energy dissipated per cycle in the circuit resistance then is the product of R and the sq of the rms current times the period T of one cycle. Ie R(Imax/sq root2)^2/F since T=1/f Q may them be calculated purely in terms of impedance ie Q=Omega L/R. Note however that the real value of L can only be calculated when the distributed capacitance of the inductor is taken into account. It should be noted that reducing the distributed capacitance and the proximately effect not only increases Q but results in improved antenna efficiency which is exactly one of the benefits of spider wound coils compared to bundle wound coils something the parrot is obviously unaware of!

                    Comment


                    • Originally posted by Doug2 View Post
                      The mathematical definition of Q of a circuit is 2pi times the ratio of the maximum instantaneous energy to the energy dissipated over unit of time corresponding to one cycle. ie Q=2pi X energy stored/energy dissipated per cycle. At the instant the max energy stored in the inductance of a resonant circuit the amount of energy stored can be expressed as1/2L(Imax)^2 where I= current and L= inductance . The amount of energy dissipated per cycle in the circuit resistance then is the product of R and the sq of the rms current times the period T of one cycle. Ie R(Imax/sq root2)^2/F since T=1/f Q may them be calculated purely in terms of impedance ie Q=Omega L/R. Note however that the real value of L can only be calculated when the distributed capacitance of the inductor is taken into account. It should be noted that reducing the distributed capacitance and the proximately effect not only increases Q but results in improved antenna efficiency which is exactly one of the benefits of spider wound coils compared to bundle wound coils something the parrot is obviously unaware of!
                      Been Googling again Doug.

                      Resonance???? Are you talking about PI and the coil in circuit????

                      Comment


                      • Originally posted by Paul99 View Post
                        Been Googling again Doug. Resonance???? Are you talking about PI and the coil in circuit????
                        What happened to your parrot cartoon here? How would you measure a Pi detector coil Q?

                        Comment


                        • Originally posted by Doug2 View Post
                          What happened to your parrot cartoon here?
                          Ignoring my post about resonance are we Doug? Google sent you in the wrong direction, didn't it.

                          So, you want a parrot cartoon.... how about this one...

                          Comment


                          • Originally posted by Paul99 View Post
                            Ignoring my post aabout resonance are we Doug? Google sent you in the wrong direction, didn't it. So, you want a parrot cartoon.... how about this one...
                            No the one you claimed was meant to be posted on another forum which led to you being reported! Why are you afraid to post it here again? Let members really see what the inner you is really like!

                            Comment


                            • Originally posted by Doug2 View Post
                              No the one you claimed was meant to be posted on another forum which led to you being reported! Why are you afraid to post it here again? Let members really see what the inner you is really like!
                              You just go on here with your ridiculing of anyone who disagrees with you, and keep up your name calling and denigration, and let everyone here see what a low key individual you are. Pray tell how you and members of your forum have terrorised an individual until he was forced to admit he had a disability that resulted in some of the responses he gave you in an attempt to get you and mates off his back. Doug, you seriously need to wake up to yourself and seek help.

                              Comment


                              • Originally posted by Paul99 View Post
                                You just go on here with your ridiculing of anyone who disagrees with you, and keep up your name calling and denigration, and let everyone here see what a low key individual you are. Pray tell how you and members of your forum have terrorised an individual until he was forced to admit he had a disability that resulted in some of the responses he gave you in an attempt to get you and mates off his back. Doug, you seriously need to wake up to yourself and seek help.
                                "Resonance???? Are you talking about PI and the coil in circuit????" Are you saying that Pi coils don't have a resonant frequency? This is a silly as your 0Hz sq wave!!! How would you measure a Pi detector coil Q? What happened to your parrot cartoon here? Obvious you are very ashamed of it and are also too spineless to allow members to see what you are really like! PS i have never revealed this before but i have a physical disability (spinal scoliosis) due to birth trauma so don't try and say I don't know about or understand what its like to have a disability!!!!!!

                                Comment

                                Working...
                                X