Hi, I have a problem understanding the Bandito. From the schematics posted earlier in this forum, I can't logically see how a single target that rings the bell in "All-Metal" mode can also ring in "Non-Ferrous" mode. Here's why:
I'll try to make this simple: Non-Ferrous channel has two legs. Let's call Ground Balance leg GB, and Discriminate leg is D.
All-Metal channel is ummh, All-Metal. There's a bell downstream.
It looks like the "GB" and "D" legs combine to form the "Non-Ferrous" channel. Ignoring polarity, for now: Non-ferrous "high" is logically [GB AND D], through comparators IC8a AND IC8b. Now, remember inverting opamps IC10a and IC10b.
Except for about four(?) degrees offset, the all-metal clock is the same as the ground channel clock. But, GB and D have an inverter, and the all-metal channel signal path has no inverter. When a target causes GB high at IC10A-1, then All-Metal should be low at IC6B-7.
So, if a target causes (G AND D) high, and rings the "Non-Ferrous" bell, how can the same target still ring the "All-Metal" bell, since GB and All-Metal are essentially opposite each other?
I have built up the circuit in LT-Spice and run similations, but the only way I can make this thing work in a virtual panorama is to fudge, - bigtime. I may as well live in my car for all I can do to breadboard this thing, and I don't have the grasp of reflection theory to "fix" things in my computer.
Please somebody illuminate me!
I'll try to make this simple: Non-Ferrous channel has two legs. Let's call Ground Balance leg GB, and Discriminate leg is D.
All-Metal channel is ummh, All-Metal. There's a bell downstream.
It looks like the "GB" and "D" legs combine to form the "Non-Ferrous" channel. Ignoring polarity, for now: Non-ferrous "high" is logically [GB AND D], through comparators IC8a AND IC8b. Now, remember inverting opamps IC10a and IC10b.
Except for about four(?) degrees offset, the all-metal clock is the same as the ground channel clock. But, GB and D have an inverter, and the all-metal channel signal path has no inverter. When a target causes GB high at IC10A-1, then All-Metal should be low at IC6B-7.
So, if a target causes (G AND D) high, and rings the "Non-Ferrous" bell, how can the same target still ring the "All-Metal" bell, since GB and All-Metal are essentially opposite each other?
I have built up the circuit in LT-Spice and run similations, but the only way I can make this thing work in a virtual panorama is to fudge, - bigtime. I may as well live in my car for all I can do to breadboard this thing, and I don't have the grasp of reflection theory to "fix" things in my computer.
Please somebody illuminate me!

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