Maybe you guys can help me with this.
I am going to be winding a few PI coils so I thought I would practice one in the time being.
I made a rig to measure inductance as per shown on this page. http://www.coilgun.info/theoryinduct...inductance.htm
Now, I'm sure this would be a suitable test for a 60Hz device, but I don't know if the frequency is suitable for detectors.
I thought I would try it anyways.
I used the calculator here to get the specs say a stock Baracuda coil at 453uH
Now the final coils will be wound with regular insulated wire but I just wanted to verify a testing procedure so I made the practice coil with enamel coated wire.
Inner Radius - 77.5 mm
Wire thickness - .46mm
Number of turns - 33
Results
Mean Radius 78.82 mm
Coil thickness 2.64 mm
Inductance - 0.462mH
So I spin a coil and test it, around 2-3 layers thick.
I could not use me resistor decade box as the test shows as it only goes down to 10ohms. I used a 25ohm rheostat instead.
I turned the rheostat until I got equal voltage across the rheostat and the coil, 2.6v.
I then got the measured the impedance on the rheostat which was 1.8ohms.(Lx)
Using the formula based on my 60Hz transformer,
L = Lx / (2 pi f)
L = Lx / 377
L = 1.8 /377
=0.004774
No matter how I move the decimal place I can't get it to line up with the "477", so I assume this number is just a coincidence for now. (The "477" would have been pretty close to the 462uH that the calculator predicted)
So I don't know if it's because of the frequency I'm using, my math or the testing rig itself. It seemed like a reasonable approach to measuring inductance with a higher voltage. (6v).
Any suggestions?
Thanks for your time.
I am going to be winding a few PI coils so I thought I would practice one in the time being.
I made a rig to measure inductance as per shown on this page. http://www.coilgun.info/theoryinduct...inductance.htm
Now, I'm sure this would be a suitable test for a 60Hz device, but I don't know if the frequency is suitable for detectors.
I thought I would try it anyways.
I used the calculator here to get the specs say a stock Baracuda coil at 453uH
Now the final coils will be wound with regular insulated wire but I just wanted to verify a testing procedure so I made the practice coil with enamel coated wire.
Inner Radius - 77.5 mm
Wire thickness - .46mm
Number of turns - 33
Results
Mean Radius 78.82 mm
Coil thickness 2.64 mm
Inductance - 0.462mH
So I spin a coil and test it, around 2-3 layers thick.
I could not use me resistor decade box as the test shows as it only goes down to 10ohms. I used a 25ohm rheostat instead.
I turned the rheostat until I got equal voltage across the rheostat and the coil, 2.6v.
I then got the measured the impedance on the rheostat which was 1.8ohms.(Lx)
Using the formula based on my 60Hz transformer,
L = Lx / (2 pi f)
L = Lx / 377
L = 1.8 /377
=0.004774
No matter how I move the decimal place I can't get it to line up with the "477", so I assume this number is just a coincidence for now. (The "477" would have been pretty close to the 462uH that the calculator predicted)
So I don't know if it's because of the frequency I'm using, my math or the testing rig itself. It seemed like a reasonable approach to measuring inductance with a higher voltage. (6v).
Any suggestions?
Thanks for your time.
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