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How to Calculate Sample Rates of Integrators

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  • How to Calculate Sample Rates of Integrators

    Hi All. I'm trying to get my head around the humble AC integrator.

    As far as I can see, it's really just a low pass filter. So when people refer to the "number of samples that are being averaged" by the integrator, I am at a loss to fully understand.

    The corner frequency (fo) is 1/(2piCR2) where R2 is the bypass resistor, and C is the bypass capacitor - both across the Opamp output and input.

    So, if R2 is 120k, and C is .1uf, then the corner frequency is 13.3Hz. Does this mean that the integrator is taking 13 samples per second? What about all the other samples in the cut-off band after fo?

    Some help would be appreciated. Thanks in advance.

  • #2
    There has been some recent talk about this Altra posted some links to topics

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    • #3
      maybe this if link works
      https://www.geotech1.com/forums/show...082#post270082

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      • #4
        Originally posted by Elliot View Post
        Hi All. I'm trying to get my head around the humble AC integrator.

        As far as I can see, it's really just a low pass filter. So when people refer to the "number of samples that are being averaged" by the integrator, I am at a loss to fully understand.

        The corner frequency (fo) is 1/(2piCR2) where R2 is the bypass resistor, and C is the bypass capacitor - both across the Opamp output and input.

        So, if R2 is 120k, and C is .1uf, then the corner frequency is 13.3Hz. Does this mean that the integrator is taking 13 samples per second? What about all the other samples in the cut-off band after fo?

        Some help would be appreciated. Thanks in advance.
        I think you're getting confused between a simple integrator and a sampling integrator. The sampling integrator includes a gating circuit (usually a jfet or a bipolar switch) that synchronously demodulates the incoming signal. Hence the reference to "number of samples".

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        • #5
          Originally posted by Qiaozhi View Post
          I think you're getting confused between a simple integrator and a sampling integrator. The sampling integrator includes a gating circuit (usually a jfet or a bipolar switch) that synchronously demodulates the incoming signal. Hence the reference to "number of samples".
          Okay. I meant an integrator with a gating circuit before it. I've looked through the myriad threads kindly suggested by 6666 (and the referenced sub-threads), and haven't yet seen a formula to calculate the number of samples per second for the attached example circuit. I'm not worried about calculating the gain of the integrator.
          Attached Files

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          • #6
            Not simple----best is Carls post that goes sample by sample to calculate integrator output.
            https://www.geotech1.com/forums/show...4582#post54582

            Setup a spreedsheet with the parameters: Cs,Rs, pulse rate, Sample time, etc. Then calculate the output at each sample time.
            Plot this to see the time response to an input step.

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            • #7
              R4 and C2 set the response in your circuit. Sample rate(Tx rate) and sample time effect the gain.

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              • #8
                Or simulate it with SPICE.

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