Garrett (pulse) XL 500

[blobber]

You not need a new pcb. Try to make a charge pump on a breadboard! You will see, that the 555 on pin3, gives 9,5V p-p, with 65 kHz.

[ripsdevala]

You not need a new pcb. Try to make a charge pump on a breadboard! You will see, that the 555 on pin3, gives 9,5V p-p, with 65 kHz.

What if i make external circuit to get 5v?
Like this one, is there any effect on the circuit?

[ripsdevala]

I dont have any clue with this one mr.Fred, i know that it would be work in the breadboard like in prometeous, the problem is in my pcb, if you have some measurement from batt to charge circuit that would help, so i will know what components is do faulty and make bc548 hot. Or if you have any other methods

[ripsdevala]

Maybe this will show the problem,
I pick all the ic and measure 555 charge socket pin.
Ground -pole batt
1. -12v
2. 12v
3. 0v
4.12v
5. 0v
6. 12v
7. 12v
8. 12v
Let me know is this correct

[reptooyep]

Maybe this will show the problem,
I pick all the ic and measure 555 charge socket pin.
Ground -pole batt
1. -12v
2. 12v
3. 0v
4.12v
5. 0v
6. 12v
7. 12v
8. 12v
Let me know is this correct

Hi,
The ground of all the circuit is the + BATTERY pole so, why still taking measurement between test point and - battery pole ?
I realy don't understand.
Without the NE555 (charge pump), you will never measure any +5v supply.
Without any chip (exept the charge pump), you can only measure supplys so :
GND (Still battery +) of NE555 and pin 1 = -5v
GND and 4538 pins 8 and 12 = -5v
GND and LM324 pin 4 = +5v
GND and LM324 pin 11 = -5v
GND and LM709 pin 7 = +5v
GND and LM709 pin 4 = -5v

If you don't have those supply, take off the 78l05 and 79l05 and look for shortcut.

[reptooyep]

just in case of, when you read BC548, left is Emitter and right is collector. For the BC558, left is collector, right is emitter.
Maybe they are simply reversed ?

[ripsdevala]

The layout is right, bc548 and bc558 have same legs CBE

[ripsdevala]

Hi,
The ground of all the circuit is the + BATTERY pole so, why still taking measurement between test point and - battery pole ?
I realy don't understand.
Without the NE555 (charge pump), you will never measure any +5v supply.
Without any chip (exept the charge pump), you can only measure supplys so :
GND (Still battery +) of NE555 and pin 1 = -5v
GND and 4538 pins 8 and 12 = -5v
GND and LM324 pin 4 = +5v
GND and LM324 pin 11 = -5v
GND and LM709 pin 7 = +5v
GND and LM709 pin 4 = -5v

If you don't have those supply, take off the 78l05 and 79l05 and look for shortcut.

Ya, okay no more -pole as ground, i think it would show the real value.
Let me test ur measurement...

[reptooyep]

The layout is right, bc548 and bc558 have same legs CBE

That's right, sorry for cofusing

[ripsdevala]

This is what i got:
+pole gnd
GND (Still battery +) of NE555 and pin 1 = -11.7v
GND and 4538 pins 8 and 12 = -5v
GND and LM324 pin 4 = +3.2v
GND and LM324 pin 11 = -5v
GND and LM709 pin 7 = +3.2v
GND and LM709 pin 4 = -5v

still have problem with 78

[blobber]

Could you please post here high resolution pictures, top and bottom side of your board?
Maybe we can see something wrong there.

[reptooyep]

I've checked the schematic and it's normal to measure —12v on pin 1 of the 555 (charge pump) cause it's powered by the battery.
On the other 555 (used for pulse generation), pin 1, you should have —5v cause your 7905 seems correct.
The only problem remain for the 7805 . How much have you on input of 7805?

[6666]

just in case of, when you read BC548, left is Emitter and right is collector. For the BC558, left is collector, right is emitter.
Maybe they are simply reversed ?

Why do you say the legs are different? all the published data says the two transistors legs are the same .

[ripsdevala]

Why do you say the legs are different? all the published data says the two transistors legs are the same .

Just wrong perception 6666, reptooyep already realized

[ripsdevala]

7808 input 3.9v

High res pic

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Side1

Side2

Side3

Side4


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