Originally posted by CrizzyD
View Post
Originally posted by CrizzyD
View Post
Coil tau = L/R = 40uH/1Ω = 40us
Peak current at turn-off is
Energy in the coil is
Power dissipated is
Now let's double the pulse width to 120us:
So doubling the pulse width more than doubles the power. Most of this gets dissipated in the PMOS because of avalanching. You can use a higher breakdown PMOS to reduce the PMOS power but the energy still needs to be dissipated so now the damping R and clamp R will get hotter. And battery life is halved.
You have two other variables to try. One is to reduce the pulse rate. Halving the rate from 2kHz to 1kHz will get you back to about the same overall power, but this reduces the integrator averaging by half, so you may lose sensitivity overall. The other is to add some series resistance to the coil. This seems counterproductive but it helps flat-top the coil current which can improve depth on higher conductors. For example, if you add 1Ω and use a 120us pulse width the peak current s now 5.7A, slightly less than before. But the current slope at turn-off is improved from 71mA/us to 7.5mA/us. Whether this actually helps depends on the target.
Which brings up the question: what are you trying to accomplish?
Comment