Ground balance (GB) is usually solved by making linear combinations of successive samples such that the sum of the ground signal is null.
Unfortunately, the same linear combinations also null for certain time constants (TC). These are called GB holes. Objects with TC near those holes escape detection if this form of GB is used.
The solution I propose is to use 3 successive samples s1, s2, s3 at times t, 2t and 4t. In the presence of pure ground (thus no targets) and assuming the usual invariant 1/t ground response, the amplitude ratios of successive samples is as follows:
s2/s1 = (1/2t)/(1/t) = 0.5
We express this as the point (0.5, 0.5) on a plane. This is the Ground point.
GP = (0.5, 0.5)
A target with TC = tau will have the following ratios:
s2/s1 = exp(-t2/tau)/exp(-t1/tau)
s3/s2 = exp(-t3/tau)/exp(-t2/tau)
We express this as the target point (exp(-t2/tau)/exp(-t1/tau), exp(-t3/tau)/exp(-t2/tau)) on a plane. This is the Target point.
This is a plot of the euclidean distance between the Target and the Ground point. They never meet, which solves the problem of the GB holes.
sqrt((exp(-10/tau)/exp(-5/tau)-0.5)**2 + (exp(-20/tau)/exp(-10/tau)-0.5)**2))
Unfortunately, the same linear combinations also null for certain time constants (TC). These are called GB holes. Objects with TC near those holes escape detection if this form of GB is used.
The solution I propose is to use 3 successive samples s1, s2, s3 at times t, 2t and 4t. In the presence of pure ground (thus no targets) and assuming the usual invariant 1/t ground response, the amplitude ratios of successive samples is as follows:
s2/s1 = (1/2t)/(1/t) = 0.5
s3/s2 = (1/4t)/(1/2t) = 0.5
We express this as the point (0.5, 0.5) on a plane. This is the Ground point.
GP = (0.5, 0.5)
A target with TC = tau will have the following ratios:
s2/s1 = exp(-t2/tau)/exp(-t1/tau)
s3/s2 = exp(-t3/tau)/exp(-t2/tau)
We express this as the target point (exp(-t2/tau)/exp(-t1/tau), exp(-t3/tau)/exp(-t2/tau)) on a plane. This is the Target point.
This is a plot of the euclidean distance between the Target and the Ground point. They never meet, which solves the problem of the GB holes.
sqrt((exp(-10/tau)/exp(-5/tau)-0.5)**2 + (exp(-20/tau)/exp(-10/tau)-0.5)**2))
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