Sorry to bother you guys. I am preparing the presentation now and I need to figure out the working principle of 'matchless metal locator'. In my opinion, at the normal condition the Rx will receive a small signal and after the amplifier
the signal voltage is still less than the 2/3Vcc so the ICB1 part will produce a high voltage. If a metal is near the coils, the received signal becomes larger and the amplified signal is larger than 2/3 Vcc so the chip could produce a square wave signal, am I right? Or the circuit works due to the change of frequency of received signal?
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matchless metal locator circuit working principle
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