Announcement

Collapse
No announcement yet.

AC or DC

Collapse
X
 
  • Filter
  • Time
  • Show
Clear All
new posts

  • #16
    Going a bit further, increasing the pulse width, increases the current, since Vpeak and PPS remaining constant this can only imply an increase in Vrms. This is verified by measuring with true RMS meter while increasing the pulse width.
    The impedance of the coil(inductive reactance) does not change because PPS and L are the same.
    One can conclude that for various pulse width of square pulses, Vpeak stays the same but Vrms changes. Hence current in coil changes.
    I sure like to get some feedback from knowledgeable people on this.

    Comment


    • #17
      Maybe put clamp meter on coil to measure current in coil.

      Comment


      • #18
        None of this is going to help. If you want to measure the current in the coil, then you have to measure the waveform. Otherwise, all you'll get is an average or RMS value, which is meaningless unless you know the waveform.

        Comment


        • #19
          It was fun while it lasted.

          Comment


          • #20
            Originally posted by markg View Post

            The only thing the meter would do is give me:
            AC voltage
            Average 4.426 volt
            Max 4.449 volt
            min 4.406 volt


            I got this information in the manual about the True RMS meter.

            Understanding AC Zero Input Beh
            avior of True RMS Meters Unlike averaging meters, which can accurately measure only pure sinewaves, True RMS meters accurately measure distorted waveforms. Calculating True RMS converters require a certain level of input voltage to make a measurement. This is why AC voltage and current ranges are specified from 5% of range to 100% of range. Non-zero digits that are displayed on a True RMS meter when the test leads are open or are shorted are normal. They do not affect the specified AC accuracy above 5% of range. The input levels that are unspecified are: ? AC voltage: below 5% of 6000 mV AC, or 300 mV AC ? AC current: below 5% of 60 A AC, or 3.00 A AC

            I think I wasted my time borrowing the meter!
            After allowing the meter to run for several minutes I noticed the max and min stayed pretty close to the stated voltages above. But after running several minutes the max voltages span is reduced due to the depletion of the batteries. Trying to apply all this to an equation I can see it would take a huge difference in voltage to increase the current only slightly. Not sure if this experiment will ever provide any concrete answer to the question:
            Does increasing the battery voltage actually increases depth capabilities?
            Every so slightly, maybe.
            Increasing capacity will increase run time? yes.............

            Comment

            Working...
            X