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I'm sure that most know all this, but I thought I would share my research.
If a detector has for example a pulsing square wave from 0 to 5V. To calculate the RMS voltage would be .707 x 5 but this is only true for a 50% duty cycle.
A Bandido in battery test has a 5V pulse with a 1/6 duty cycle. To calculate the RMS, take the square root of 1/6 which is a result of .408 and multiply the peak voltage by this.
The 5V I measured was after the 150 ohm interal resistor and with 250 ohm load connected. The result of E^2/R = 16.6 mW.
So basically, peak times the square root of the duty cycle is the rms voltage.
What is weird about square waves is that if the wave is still 5V peak to peak, but above and below zero (+/- 2.5v) the Vrms is equal to the peak voltage of 2.5, no mater what the duty cycle is.
If a detector has for example a pulsing square wave from 0 to 5V. To calculate the RMS voltage would be .707 x 5 but this is only true for a 50% duty cycle.
A Bandido in battery test has a 5V pulse with a 1/6 duty cycle. To calculate the RMS, take the square root of 1/6 which is a result of .408 and multiply the peak voltage by this.
The 5V I measured was after the 150 ohm interal resistor and with 250 ohm load connected. The result of E^2/R = 16.6 mW.
So basically, peak times the square root of the duty cycle is the rms voltage.
What is weird about square waves is that if the wave is still 5V peak to peak, but above and below zero (+/- 2.5v) the Vrms is equal to the peak voltage of 2.5, no mater what the duty cycle is.
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