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  • #76
    Hello JC1,

    The method I mentioned has disadvantages and advantages. I spent some time converting from the java Circuit Simulator to LTSpice. Here are the results:

    Code:
    No losses are included.
    
    Nugget diameter: 0.1" (2 nH, 3200 uOhm)
    My 5 usec Tperiod:		920.75 mV
    Typical 18 usec Tperiod:	953.60 mV
    -----------
    1"
    My 5 usec Tperiod:		10.08 mV
    Typical 18 usec Tperiod:	12.92 mV
    -----------
    10"
    My 5 usec Tperiod:		1.93 uV
    Typical 18 usec Tperiod:	2.59 uV
    
    ---------------------------------
    
    Nugget diameter: 0.1" (20 nH, 320 uOhm)
    My 9 usec Tperiod:		498.34 mV
    Typical 18 usec Tperiod:	953.60 mV
    -----------
    1"
    My 9 usec Tperiod:		11.41 mV
    Typical 18 usec Tperiod:	12.92 mV
    -----------
    10"
    My 9 usec Tperiod:		2.23 uV
    Typical 18 usec Tperiod:	2.59 uV
    
    ---------------------------------
    
    Nugget diameter: 0.1" (200 nH, 32 uOhm)
    My 18 usec Tperiod:		235.30 mV
    Typical 18 usec Tperiod:	953.60 mV
    -----------
    1"
    My 18 usec Tperiod:		12.50 mV
    Typical 18 usec Tperiod:	12.92 mV
    -----------
    10"
    My 18 usec Tperiod:		2.59 uV
    Typical 18 usec Tperiod:	2.59 uV
    The nugget R & L values are from my calculations for a nugget that has resistance of near lead. The "Typcial 18 usec Tperiod" is a typical pulse where the coil charge time is 7.5 times longer than the collapsing field time. As you can see, the typical pulse method gives slightly better results, but this assumes you can recycle the energy as efficient as my method.

    Equal power was used for all the above examples. Also I considered the fact that 4 times as many gathered samples per second yields twice the SNR. So the above results were resulting signal from nugget multiplied times square-root of sample rate. Also, if the pulse was half the time, then I made sure the coils voltage was doubled so as to maintain the same resulting peak current on the coil. The total energy put into the coil is equal to I^2. Also if the sample rate was 4 times greater then I cut the coils voltage by half. This is because four times as many pulses occur per second. Cutting the coils voltage in half equals to one-fourth the energy thereby making it equal in power dissipation.

    Here are some reasons to use my square symmetrical pulse method:

    1. To work with one voltage level; e.g. 6 volts. Rather than say 12 volts for charge and 400 volts during collapse time. Or in my case it would be more like 180 mV charge and 6 V during collapse time since I'm using a 1-turn coil.

    2. To simply the design. I'm not an expert circuit designer and struggle with gotchas of circuitry that you pros know about. Well, they seem like gotchas to me, lol. It is very important to recycle the collapsing magnetic fields energy. So if I went with the typical design then I would have to charge the coil at say 180 mV and then recapture the collapsing field into a 6 volt source. I could use a 180 mV battery to charge the coil, lol, and then collapse into a capacitor that's charged to 6 volts and then recycle a small amount of the caps energy back into the 180 mV battery. Or I could do the reverse and use a 6 V battery and somehow efficiently maintain ~180 mV on a cap and then use that cap to charge to coil and then collapse the field directly into the 6 V battery. Either way you are going to lose energy in the energy conversion process. Perhaps an efficient method is to have a dozen 180 mV batteries. I could use one of the batteries to charge the coil and then collapse the field into all 12 batteries. Then every so often I would have to rotate the batteries. Are there any good 180 mV batteries? In my case 600 mV sound better anyway. Perhaps another method is using a tiny 600 mV battery and a large 6 V battery. The tiny 600 mV would charge the coil and the collapsing field would go into the 6 V. Then perhaps every minute or so the circuit would automatically charge a toroid and dump its energy into the 600 mV battery. This could perhaps achieve 90% efficiency. Last year I was working on something else and achieved 85% efficiencies, but efficiency was not my goal. Another option is using a transformer, but at a glance I don't care for that idea.

    3. The present design seems almost as efficient as the typical method except I do not have to waist a lot of energy working with wide voltage sources and energy conversions. I can simply charge the coil with the 6 volt battery and then collapse the field back into the same 6 volt battery. According to my calculations, "my 18 usec Tperiod" yields equally efficient results all the way up to nuggets that are a few inches in diameter. A 10" nugget is over half as efficient as the typical method. Although, according to my calculations, I'll be able to detect a 10" nugget farther than I'd ever want dig. ... 10" nuggets, lol.

    A few designs ago I had a simple fix for the big nugget issue. The fix was simply shorting the coil in-between coil charge and collapsing field periods for several usec's. This allowed the nuggets current to significantly collapse during this "wait period". In other words, a voltage is applied to the coil. So now there's current in the coil. Then the voltage is removed and replace with a short across the coil. This short maintains the coils current. So if the 1-turn coil is 2 uH and the transistors resistance is 0.01 ohms, then after 10 usec the coil's current drops 5%, or after 20 usec a 10% loss. That's not too bad. Note that the nuggets current will collapse during this coil shorted period because the coils di/dt is extremely low. Then the coil short is removed and the collapsing field is directed across the same 6 V battery.

    Perhaps I'll put the "coil short" feature back in if the detector doesn't scan as deep as desired, but that will yield a 5% to 10% loss. Not sure if it will pay off. For now, it seems this method is better for nuggets smaller than 1", unless you use a really efficient method of working with wide voltage sources and energy conversions. You could use the dozen-battery method and rotate the batteries, but that doesn't sound like fun. Otherwise I'm wondering just how much loss there would be. Perhaps 20% to 40%? If you know of a method that's over 90% efficient then I would consider using the typical pulse method. Where there's a will there's a way.

    Peace,
    Paul

    Comment


    • #77
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      Comment


      • #78
        JC1

        Hi Paul,

        Thanks for the reply, I'm still not sure exactly what you are doing here, though I followed most of what you said. I think.

        Signal averaging is fine, as long as you are digitizing the noise to many bits and not just one or two. It can also beat with certain frequencies actually increasing the noise.

        It appears your approach will require wider bandwidth, so will need to include this. Around the US don't want to get near AM radio band 560kHz to 1.05 MegHz or will start picking them up.

        The energy recovering method by charging batteries is very inefficient so will need capacitors or something here.

        Interesting, I will reread this and see if I can figure it out?

        JC

        Comment


        • #79
          Hello JC1,

          I'm going to think out loud here, so please correct any obvious math errors and such.

          Originally posted by Unregistered
          Signal averaging is fine, as long as you are digitizing the noise to many bits and not just one or two.
          I wish that I was using a Microcontroller! Unfortunately for now it's entirely analog.

          Originally posted by Unregistered
          It appears your approach will require wider bandwidth
          How do you figure that? I'm not sure exactly what you're referring to. You mean because I'm in the MHz range rather than KHz? Perhaps if I'm near an AM radio station. On the other hand, KHz terrestrial noise is killer compared to MHz noise. KHz region is flooded with terrestrial noise from the day and night atmospheric. Galactic noise is not far behind in addition to quite rural noise. I'm looking at a noise table and I'd say KHz noise is roughly 150 dB over kTB than MHz noise. So I guess it depends how close my unit will be to an AM radio station, but I can always adjust the base frequency to the quietest band, which would help. If I can out run those radio stations then there should be a huge payoff. Unfortunately nature's terrestrial noise is not so forgiving being that it spreads across the entire VLF band. Additionally, terrestrial noise is everywhere. I guess the proof will be in the pudding, lol.

          Please see the Terrestrial Noise graph at
          http://www.broadcastpapers.com/white...andVHF_348.pdf

          Radio stations would be included in Residential, Rural, or Quite Rural noise. If you're smack dead in the city then it would be Residential. I'm not exactly sure what their definition of "Quite Rural" is but it's probably small towns and farming communities. So I'm guessing way out in the desert is quieter than even quite rural. Residential would be flooded with AM MHz radio station noise, but as you can see from the graphs it's a drop in the bucket compared to terrestrial KHz noise. One KHz would be far off the screen, but you can get an idea.

          Originally posted by JC1
          The energy recovering method by charging batteries is very inefficient so will need capacitors or something here.
          Hmmm, I calculate the opposite. One great thing about the collapsing fields from inductors is they match the load. Lets say I have 10 amps in the coil, then I pull the plug. So the inductors wants that 10 amps and it will collapse at whatever speed it takes. If the battery is 12 V and resistance is 0.01 ohms then the inductor will collapse at a rate so that its voltage is 12.1. 12.1 – 12.0 = 0.1 volts. 0.1 V / 0.01 ohms = 10 amps. Lets take another example and say the coil is at 3 amps and battery is 7 volts and R is 0.02 ohms. The field will collapse at a rate so that its induced voltage is 0.06 volts over the batteries voltage, regardless, which is 7.06 volts.

          As you can see in both examples, nearly all the energy is across the battery, not the resister.

          Now lets take the other path and discharge into a cap. So the coil has 10 amps, 12 V, 0.01 ohms. The cap is initially charged to 12 volts. When you remove the voltage on coil it wants that 10 amps. So the coil will induce 12.1 volts. That gives 10 amps. So what's the caps voltage after the coil fully discharged? You'll need a decent size cap, meaning electrolytic cap. We're already getting inefficient. Here's an example:

          One turn coil is 2 uH at 20 amps, which yields 1/2 I^2 L = 0.5 * 20A^2 * 2 uH = 0.0004 J.
          Cap is pre-charged to 12 volts, which equals 1/2 V^2 C = 0.5 * 12V^2 * 100 uH = 0.0072 J.
          So the final equal is:
          0.0004 J = 1/2 V^2 C - 0.0072 J
          V = 12.33 V.

          So our cap went from 12 V to 12.33 V. We have a little annoying problem in that our batter is 12 V, but the cap is 12.33 volts. As you know, if you place the cap across the battery then 0.33 volts is wasted. Over all we're wasting something like 0.17 volts. We have an electrolytic cap, which is not efficient from the start and you need to make sure the cap is very close to the batteries voltage. One might initially think to start with a lower charged cap, say 11.8 volts. If so, then how's the cap going to always start at 11.8 volts when the battery is 12 volts? If we discharge the cap onto the battery then caps final voltage needs to be at least 12 volts. In our example, starting with 12 volts is even unrealistic. More like 12.1 volts. So the coil charges the cap to about 12.4 volts. That's nearly half a volt loss when discharging the cap into the battery.

          How would you use a cap to achieve better results then an inductor directly to the battery? This seems impossible because the only wasted energy using my direct approach is the resistance from the transistors. The 1-turn coil has no appreciable resistance. Good battery resistances can be in the milli ohm range. So even if you use a cap you will lose at least that same energy loss from transistors.


          Hey, I've been playing a little with the idea of using a dozen tiny batteries to achieve an efficient typical pulse. You know, slow charge, fast discharge. The 1-turn coil could get away with 1.2 volts, possibly as high as 2 volts. Much higher and I'd need to carry a car battery, lol. Figure 2 uH for 20 usec charge time. Here's a battery table:

          http://www.batteryspace.com/index.as...S&Category=489


          Lead acids are heavy, low cycle life, and 2V per cell. The NiCd look interesting because it's the only one that has a "+" after cycle life-- "500+" I guess they're suggesting NiCd have best cycle life. They're very cheap and 1.2 V per cell. NiMH hold twice the energy as NiCd. Li-ion are best because they're light but very expensive to maintain / replace. I could use Li-ions but would require 2-turn coil. Perhaps we can have our cake and eat it.

          Paul

          Comment


          • #80
            JC1

            Hey Paul,

            your Terrestrial Noise graph is not that.

            It is db noise OVER ktb which ktb goes down with freq. make this chart go up at low freq. It illustrates the difference between TerrNoise and receiver noise (which is what I was talking about and you missed the point) which is usful for the purpose of this paper.

            battery point (you missed this point as well)

            The coulometric charging efficiency of nickel metal hydride batteries is typically 66%, meaning that you must put 150 amp hours into the battery for every 100 amp hours you get out. The faster you charge the worse this gets.

            http://www.powerstream.com/NiMH.htm

            Too much explaining Paul.

            Comment


            • #81
              Originally posted by Unregistered
              It is db noise OVER ktb which ktb goes down with freq. make this chart go up at low freq. It illustrates the difference between TerrNoise and receiver noise (which is what I was talking about and you missed the point) which is usful for the purpose of this paper.
              Could you please explain? I have no idea what you're saying. Why would kTB go down with frequency? "k" is a constant. "T" is temperature. "B" is bandwidth, not frequency. The graph of interest is on page 6 of that pdf link. I'm interested in what you are trying to say because I always thought it was common knowledge that terrestrial noise increases as the frequency decreases.


              Originally posted by Unregistered
              battery point (you missed this point as well)

              The coulometric charging efficiency of nickel metal hydride batteries is typically 66%, meaning that you must put 150 amp hours into the battery for every 100 amp hours you get out. The faster you charge the worse this gets.
              But it was stated in the last post that my design could use any battery type.

              I'm not sure what you're trying to say. It seems that if you charge the battery with either C's or L's then you still get battery-charging inefficiencies.

              Thanks for being patient!
              Paul

              Comment


              • #82
                JC1,

                Regarding batteries and caps, are you saying to only discharge into the cap and then use the batteries to add a little extra to the caps to make up for losses and then use the cap as the main power source for the coil? That sounds promising. I'll think about that.

                Paul

                Comment


                • #83
                  JC1

                  Hi Paul,

                  well I was pretty blunt and you took that well.

                  Yes the batteries make up for loses with pulse to pulse energy recovery into caps. very good you figured it out.

                  Receiver noise goes up with bandwidth so noise depends on bandwidth. electronic noise. environment depends on your band. pick the wrong band and get whatever transmitter etc.

                  The A.M. radio stations carry from town to town pretty good so getting out doesn't always help alot and depending on which way out of town you go, you may find the xmitter out in the country away from town with its tall tower.

                  And they are AM modulated which can make for more fun.

                  Comment


                  • #84
                    Too bad nickel batters are so inefficient. I guess Lithium's are not much better.

                    You could discharge into an efficient cap and use an efficient transformer to keep the caps voltage up during sample delay. There's still some transformer loss, but sounds a lot better than 66% efficient nickel batteries.


                    Originally posted by JC1
                    Receiver noise goes up with bandwidth so noise depends on bandwidth.
                    Wait a minute. How do you figure bandwidth goes up? The pulses frequency is higher, not bandwidth.

                    Paul

                    Comment


                    • #85
                      JC1

                      Paul,

                      I assummed you wished to receive the higher frequency you transmitted.

                      My bad.

                      Comment


                      • #86
                        JC,

                        Some of the more popular designs here such as Dave's and Eric's seem to be in the VLF KHz region. Lets just say my latest design (it changes on daily basis, lol) is from the 50KHz to 1MHz. OK, charging batteries is bad idea unless li-ions are over 90% eff. So I have no other option but to use slow pulse charge / fast discharge. This type of pulse has frequencies at 50 KHz, 100 KHz, 150 KHz, 200 KHz, 250 KHz, 300 KHz, 350 KHz, 400 KHz, etc. See attached image. So there's no frequencies at 50.1 KHz, or 50.001 KHz, or 49.999 KHz, or 100.01 KHz, etc. My base frequency's 50KHz. Same thing applies if I used a base frequency of 9 KHz; i.e., no frequencies at 9.001 KHz. So the limiting factor is Q. Well, as you know, we don't want to sample for 10 minutes otherwise the detectorist would have to swing the machine at snails pace. I figure a sample every half second is fine. That's 2 Hz. My design uses banks of high Q simple filters-- the more the merrier I figure anywhere from 10 to 20 filters should work well enough for my bandwidth needs. So if I use 10 filters (10 frequencies) then the bandwidth is 2 Hz * 10 = 20 Hz. Regardless if the base frequency is 9 KHz or 50 KHz we still get the same bandwidth.

                        The question is what's the noise spectrum in the CA, AZ, and NV deserts.

                        Paul
                        Attached Files

                        Comment


                        • #87
                          I keep forgetting to mention the most important factor. Higher frequencies equates to more samples. More samples equates to higher snr.

                          Paul

                          Comment


                          • #88
                            JC1

                            Hi Paul,

                            So I'm guessing here, you are talking about building many High Q bandpass filters for each harmonic? Need an amp for each one of those. Not sure how you got from the output filter/S.A.T./swingspeedfilter/whatever to the input 20 Hz bandwidth.

                            Well now this should be alot of fun to tune and keep in tune with time and temperature.

                            20 Hz bandwidth, with 400,000 Hz center frequency. Yep, perty high Q.

                            Comment


                            • #89
                              JC1

                              Higher frequencies equates to more samples, but only gives higher signal to noise, if samples are equal amplitude.

                              If higher frequencies make tiny little receive signals then adding up a million of em may not give crap.

                              Comment


                              • #90
                                JC1

                                Hi Paul,

                                Oh, by the way, we don't actually want to receive the xmit signal, we really want to receive the decay of the eddy current signal in the receiver. This will have different spectrum but is related to the xmit freq by rate of occurance.

                                Comment

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