Function of Cemented Ceramic Caps Connected Series Fashion.

[ToddB66]

Greetings Everyone!

I will use AA dry cell non-rechargeable batteries and ceramic capacitors for an analogy to pose a question, as follows:

The AA's can be connected series fashion in a DC circuit with the result that their output Volts (and Amps) accumulate when a load is applied, i.e. two 1.5v batteries produce 3v or slightly more when new and for some time afterward as they begin to degrade.

OK, so my question is "what is the effect on the output/input functionality when two new cemented ceramic capacitors of some value are connected series fashion in a DC circuit and then a load is applied?".

I'm really not looking for a string of physics formulas; just please answer briefly in general fashion if you can.

Thanks,
ToddB66

[Mr.Jaick]

Hi
As soon as you connect the Load or the Supply you will have a transient current flowing through the DC circuit and after a while when it decays to Zero you will have Zero current through the load and zero voltage across the load rendering the DC circuit into an open circuit because capacitors do not pass Direct-Current.
A variable load will not change this(eg. A pulsed switch)
But a variable supply (eg. sine source) can go through and reach the load.

[ToddB66]

Hi
As soon as you connect the Load or the Supply you will have a transient current flowing through the DC circuit and after a while when it decays to Zero you will have Zero current through the load and zero voltage across the load rendering the DC circuit into an open circuit because capacitors do not pass Direct-Current.
A variable load will not change this(eg. A pulsed switch)
But a variable supply (eg. sine source) can go through and reach the load.

Mr.Jack,

I'm sorry to say I made errors in my post #1, as follows:

• The title should have read "Function of Cemented Ceramic Resistors Connected Series Fashion.
• The message body should have read as follows:

03-10-2024, 11:16 AM
Greetings Everyone!

I will use AA dry cell non-rechargeable batteries and ceramic resistors for an analogy to pose a question, as follows:

The AA's can be connected series fashion in a DC circuit with the result that their output Volts (and Amps) accumulate when a load is applied, i.e. two 1.5v batteries produce 3v or slightly more when new and for some time afterward as they begin to degrade.

OK, so my question is "what is the effect on the output/input functionality when two new cemented ceramic resistors of some value are connected series fashion in a DC circuit and then a load is applied?".

I'm really not looking for a string of physics formulas; just please answer briefly in general fashion if you can.

Thanks,
ToddB66

[Carl-NC]

Are you asking how resistors in series behave? I don't understand the references to "cemented" and "ceramic."

[ToddB66]

Are you asking how resistors in series behave? I don't understand the references to "cemented" and "ceramic."

Hi Carl-NC..........Yes, I'm asking specifically "How would two or three axial wire Cemented Ceramic Resistors connected in series behave in a Live circuit, generally speaking?".

The link on eBay below (If the dxxxx thing works) shows an example of where I got the terminology "Cemented Ceramic", which I take to mean powdered ceramic mixed with some kind of adhesive (or "cement") and the resulting substance poured into multi-cavity molds of some type with wire strung tight through the molds (To be automatically trimmed to length at some point down the production line.). The molds then conveyed through ovens for the mix to quick-cure, ink-stamped, laser-eye inspected and defectives kicked out and the rest dumped out into plastic bags, etc..,etc. and on to the stockroom. All done on Chinese or Japanese high-speed production lines.

https://www.ebay.com/itm/13491726065...tomid=e40f0ac1

ToddB66

[Carl-NC]

Oh, I see. These are high-power resistors, the ones I have are 10W. They should behave like any other resistor, except that some are made as "wirewound" resistors and will have a small inductance as well. Usually no more than a few uH.

[kt315]

maybe you have to read What is the internal resistance of a battery?
if the matter is unknown.

and for some time afterward as they begin to degrade

Why is it Important to Measure Battery's Internal Resistance? | Hioki

[ToddB66]

Oh, I see. These are high-power resistors, the ones I have are 10W. They should behave like any other resistor, except that some are made as "wirewound" resistors and will have a small inductance as well. Usually no more than a few uH.

Carl-NC.....With respect to the two questions below starting "How", .I'm wondering if the resistance increases or reduces if two of these resistors are connected in series in a Live circuit.

QUESTIONS:

• Does "wirewound" mean that this type has an inductance coil inside?
• How do "non-wire wound" behave if two are connected in series in a Live circuit?
• How do "wire wound" behave if two are connected in series in a Live circuit?

ToddB66

[Carl-NC]

Resistors all generally behave the same way. In series, the values simply add. There can be 2nd order effects, like inductance, temperature changes, and noise that vary amongst resistor types, and whether these effects are important depend on the application. Do an Internet search on wirewound resistors to see how they are constructed.