Confusing Power Supply Connections - Directed to Carl-NC

[ZuMi77]

This is directed to Carl-NC.

Dear Carl,
Kindly check the attachment. The power supply connections are very confusing; point D looks like it is connected to the positive side of B2 and to the ground at the same time. The whole connections are not understood. Could you explain it?
If we use only one battery, how to connect it? What modifications are needed in this case?

[Carl-NC]

It's correct, just upside-down. If it makes it easier, label D as +3V and A (or B) as ground. To use a single battery (assumed be 3V or more) you will need a rail splitter of some kind to generate the C voltage.

[ZuMi77]

It's still very confusing. I'll label D as +3V and A (or B) as ground. In this case E should be +3V, right? I have added some labels to new attachment.

This is how it looks like to me:
Condition 1: 1-2 & 5-6, the current comes from the positive side of B1, enters the switch at point 6 and exits the switch at point 5 all the way to point C.
Condition 2: 2-3 & 6-7, the current comes from the positive side of B1, enters the switch at point 6 and exits the switch at point 7 all the way to point C.

I can't see any difference between the two conditions; B2 is not (activated) in condition 1.

I would appreciate any drawing that could simplify it.

Thanks for your patience. It's really very confusing; the whole circuit is easy to understand except for this part (power supply connections).

[kt315]

a difference is just a current from the power supply. anotherway we say here - different TX POWER.
in one case it's limited by 100 Ohm resistor, in second 470 Ohm. so in second you have approx POWER/5 (470/100) less energy going in a ground.

[ZuMi77]

Kt315,
Thanks for your reply. That's very easy and already understood. My question is about something entirely different.

[Carl-NC]

Redrawn for clarity:


You can place the ground at A, C, or D. D seems least obvious.

[ZuMi77]

Thank you, Carl. The redrawn diagram made it easy to understand now.

Kindly check the attachment. Is that point E? I added E to the second attachment I have uploaded.

I really appreciate your support.

[nejdet]

Thank you, Carl. The redrawn diagram made it easy to understand now.

Kindly check the attachment. Is that point E? I added E to the second attachment I have uploaded.

I really appreciate your support.

Е=D. Interesting scheme! Do you have a diagram of the receiver? If possible, could you post it here? Thank you!

[Carl-NC]

Yes, D & E are the same.

[ZuMi77]

Е=D. Interesting scheme! Do you have a diagram of the receiver? If possible, could you post it here? Thank you!

This is the IC-67 project. I have attached the article.

[nejdet]

This is the IC-67 project. I have attached the article.

Thank you!