Jase, the circuit in posting #28 calculates difference of two integrals.
The first integral is calculated during the window of first sample. The value is a negative DC voltage in output because appears with inverted polarity of input voltage. Integrating capacitor is C6.
The second integral is calculated during the window of second sample. Integrating capacitor is C5. During integration increases DC level in output. If the value of second integral overcomes negative value of the first integral, the output becomes positive, ie the target is accepted.
Therefore to achieve acception of nonferrous metals, we can:
1. Attenuate amplitude of first sample or increase amplification at second sample.
2. Change sample delay of the second sample.
3. Change integrating window (duration) of first or second sample.
With these measures we can eliminate response of some targets - the diferrence of two integrals is zero.
The first integral is calculated during the window of first sample. The value is a negative DC voltage in output because appears with inverted polarity of input voltage. Integrating capacitor is C6.
The second integral is calculated during the window of second sample. Integrating capacitor is C5. During integration increases DC level in output. If the value of second integral overcomes negative value of the first integral, the output becomes positive, ie the target is accepted.
Therefore to achieve acception of nonferrous metals, we can:
1. Attenuate amplitude of first sample or increase amplification at second sample.
2. Change sample delay of the second sample.
3. Change integrating window (duration) of first or second sample.
With these measures we can eliminate response of some targets - the diferrence of two integrals is zero.
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