Hi all,

How far is infinity? The magnetic flux surface integral for the external inductance Le of the straight wire must go from its center position (if you place it at x=0) to infinity.
I have a 1 m lenght of wire of lets say 10 cm wire radius. Integration from 0.1 m to 10 m enough? Or 100 m far way? Let's say 1 km ok? Or should I take 1 million km? Upto Pluto, that should be really save I think.
You can't imagine what comes out. The magnetic field diminishes with 1/r², where r = distance. But the flux area gets very very large which compensates 1/r² behaviour for the external inductance.
55.5 km to 555.5 km integration delivers approx. 1 million part of 1 µH.
555.5 km to 500555.5 km (half million km) delivers 1.84e-007 µH part. You see, where I should take my integration limits for 0.1 % accuracy. 100 m - 500 m far away for a 1 m wire length. For short wires (1-5 mm), which is usual, 10 - 50 m.
I have to find a better formula for the real internal inductance Li. Something, which can be calculated quickly instead of making it via EMF simulations, which take longer time to calculate.
This is the missing part of my inductance calculation. The self internal inductance of a straight wire piece (usually very short). This is missing in my inductance calculations due to the integration method, which is subtracting it to zero.
Or I make an accurate lookup table and interpolate it. Or find the formula by myself.
Then I can say, whether Maxwell (the god father of EMF) and the other gurus made it correct or not.

Aziz

How far is infinity? The magnetic flux surface integral for the external inductance Le of the straight wire must go from its center position (if you place it at x=0) to infinity.
I have a 1 m lenght of wire of lets say 10 cm wire radius. Integration from 0.1 m to 10 m enough? Or 100 m far way? Let's say 1 km ok? Or should I take 1 million km? Upto Pluto, that should be really save I think.

You can't imagine what comes out. The magnetic field diminishes with 1/r², where r = distance. But the flux area gets very very large which compensates 1/r² behaviour for the external inductance.
55.5 km to 555.5 km integration delivers approx. 1 million part of 1 µH.
555.5 km to 500555.5 km (half million km) delivers 1.84e-007 µH part. You see, where I should take my integration limits for 0.1 % accuracy. 100 m - 500 m far away for a 1 m wire length. For short wires (1-5 mm), which is usual, 10 - 50 m.
I have to find a better formula for the real internal inductance Li. Something, which can be calculated quickly instead of making it via EMF simulations, which take longer time to calculate.
This is the missing part of my inductance calculation. The self internal inductance of a straight wire piece (usually very short). This is missing in my inductance calculations due to the integration method, which is subtracting it to zero.
Or I make an accurate lookup table and interpolate it. Or find the formula by myself.
Then I can say, whether Maxwell (the god father of EMF) and the other gurus made it correct or not.

Aziz
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