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Actual Compass XP-PRO main board rev:F schematic
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Interesting. I was about to do something similar for both disc and GB adjustment in new IGSL like what you have here for Disc.
There are a few worthy details to observe, but generally I don't like it. Too slow.
That 430Meg makes no sense. It gives a time constant of about 20 minutes, and I can't see it reasonable for a SAT, or any kind of drift. Perhaps I don't understand its purpose well enough, but so far I'm lost. Heck, 1N4148 have larger leakage current than that. In that sense, those diodes make perfectly no sense in conjunction with 430Meg.
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Originally posted by Davor View PostInteresting. I was about to do something similar for both disc and GB adjustment in new IGSL like what you have here for Disc.
There are a few worthy details to observe, but generally I don't like it. Too slow.
That 430Meg makes no sense. It gives a time constant of about 20 minutes, and I can't see it reasonable for a SAT, or any kind of drift. Perhaps I don't understand its purpose well enough, but so far I'm lost. Heck, 1N4148 have larger leakage current than that. In that sense, those diodes make perfectly no sense in conjunction with 430Meg.
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XP-PRO Main corrected.pdfSorry, I saw that before about the diodes and forgot to correct it. The diodes are there to clip large signals. I left off the ground.
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Originally posted by DavidB View Post...I checked it with a meter.
Let me put it a bit differently... If I wanted a 20 minutes time constant, I'd not rely on a component that can be spoiled with a mere sneeze.
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OK, I believe you. But it still bugs me.
The voltage at its end is well below 1V, and hence the current through that resistor is max ~1nA. With input bias current of a LF444 at 50pA what you say kind of makes sense, but not so much in combination with diodes which suggest reducing the impact of a target on such compensation, and focusing more on the very offset in absence of a target. It looks more like a clever SAT function, and in that case the resistor is too big. If you need only leakage compensation, it would require a potentiometer connected to power rails, and a huge resistor, but no feedback.
I'm still confused.
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